Fermat's Last Theorem
So we left things at all solutions of
which can be written as
  
 
for integers s>t>0 such that gcd(s,t)=1 with   . In particular, there ARE integer solutions of that equation (1);
so what about
 . In particular, there ARE integer solutions of that equation (1);
so what about
  
 
One observation is that, if n=pq, then
  
 
and
  
 
so that we simultaneously have solutions for all powers which are factors of n. Thus it suffices to ask if we can solve
  
 
for primes p: if we can't solve it for the prime factors of n, then we can't solve it for n itself.
Since we CAN find solutions for p=2, it's certainly possible that we have
solutions for   , for
 , for   . Fermat, however, took care of that....
 . Fermat, however, took care of that....
Andrew Wiles recently (1994) proved that no solutions in integers exist for any power n greater than 2. In this section, we see how Fermat (who professed to have a proof of this theorem) solved the case of n=4.
Theorem 11.3: The Diophantine equation   has no solution in
the positive integers x, y, and z.
  has no solution in
the positive integers x, y, and z.
Proof: by Fermat's method of ``infinite descent'': one obtains from a triple a strictly smaller triple, and so on ad infinitum; but the positive integers cannot be reduced ad infinitum - contradiction!
Corollary: The equation   has no solution in
the positive integers x, y, and z.
  has no solution in
the positive integers x, y, and z.
Corollary: The equation   has no solution in
the positive integers x, y, and z.
  has no solution in
the positive integers x, y, and z.
Hence, the only exponents of interest left to prove are odd primes....
Theorem 11.4: The Diophantine equation   has no solution in
the positive integers x, y, and z.
  has no solution in
the positive integers x, y, and z.
``It is impossible to write a cube as a sum of two cubes, a fourth power as the sum of two fourth powers, and, in general, any power beyond the second as a sum of two similar powers. For this, I have discovered a truly wonderful proof, but the margin is too small to contain it.''
Fermat proved the case n=4, and hence n=4k.