Checkpoint 4 Answers

Area under curve ${\displaystyle =}$ (average height) ${\displaystyle \times }$ (length of interval),

average height ${\displaystyle =}$ (area under curve)/(length of interval),

average height ${\displaystyle =\frac{1}{b-a}{\int }_a^{b}f\text{(}t\text{)} dt}$.