Checkpoint 1 Answers

  1. `s_20 = 0.6688`

  2. `text(ln) 2 = 0.6931` — it's possible that this is the limiting value.

  3. The error must be less than `1//21 = 0.0476`. The actual error is `text[|] s_20 - text(ln) 2 text[|] = 0.0244`.