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Some of you suspected that I was asking the definition of a function again, which is one reason why I started it for you: $f'(x)=$....
I also gave you the big hint that it involved limits. It's why we spend so much time on limits.
\[ f'(x) = \lim_{h\to 0}\frac{f(x+h)-f(x)}{h} \]
A Haiku, by A. Long.
limit -- as $h$ goes
to zero -- change in function
over step-size $h$.
Note: three things have to happen:
Otherwise $f$ is discontinuous at $a$.
There are various kinds of discontinuity (which we've already seen):
This function has a limit at zero (-.5), but is not defined there. If $f$ is not defined at $x=0$, then it cannot be continuous there. We can fix this, by the way.... Just define $f(0)$ to be the limit (the closed dot in the graph above).
If $g$ is continous at $x=c$ and $f$ is continous at $g(c)$ then
$F(x)$
is continuous at .